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Implication : After the reversion, numsi <= ... <= numsn-1. The next permutation of nums only change numsi-1: by swapping position of numsi-1 and first numsj greater than it behind it. Reference Solution
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Implication : Remove the last value of current sequence while next number is less than it. Then the result sequence will be smallest one. If k > 0 at the end, it will also be in ascending order. Reference Solution
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Implication : After day 1, cells0 and cells7 must be 0. So the total number of states is reduced from 2^8 to 2^6, which will save time and space. Reference Solution
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Hint : It's modified lexicographic comparation.
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Hint : Start delete after finding duplicated nodes, then delete last node (head) at last. Reference Solution
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Implication : If we move the higher side inside, the area must be smaller. Reference Solution
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Implication : First multiply the numbers literately from left side, then do it again from right side. Reference Solution First thought with O(n) space complexity : To improve, we can reuse the result array :
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